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Amazon OA1 + OA2 3/2 due

[复制链接] |试试Instant~ |关注本帖
zhushigang 发表于 2016-3-3 07:34:50 | 显示全部楼层 |阅读模式

2016(1-3月) 码农类General 硕士 全职@Amazon - 内推 - 在线笔试  | Other | fresh grad应届毕业生

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Timeline: 2/4内推, 2/10收到RC5邮件填表,2/17收到OA1(2/24 due),2/24提交,2/25收到OA2(3/2 due),3/2提交

OA1:
debug: 地里面经都有,无难度
reasoning: 老题,快递费+6人桌. visit 1point3acres for more.
coding: sliding window minimum (leetcode #239 最大变最小)

OA2:
work simulation: 略
coding: BST min path,Round Robin

附上根据地里面经总结的coding题:. 1point3acres
OA1:
1. Overlap rectangle
.1point3acres网
2. K closest points

3. window sum

4. longest palindromic substring
https://leetcode.com/problems/longest-palindromic-substring/

5. merge two linked list
https://leetcode.com/problems/merge-two-sorted-lists/

6. two sum count / do not count duplicates
. 1point3acres
7. Check subtree. from: 1point3acres

8. Valid Parentheses
. 围观我们@1point 3 acres
9. reverse second half of linkedlist

10. graycode check.留学论坛-一亩-三分地

11. rotate String
. 留学申请论坛-一亩三分地
12. remove vowel

13. Search Matrix II. 牛人云集,一亩三分地

14. Sliding window minimum
https://leetcode.com/problems/sliding-window-maximum/

15. optimal Capacity

16. The maximum of minimums of pathes in matrix
-google 1point3acres

OA2:
1. Round Robin Scheduling: . visit 1point3acres for more.
Given an array of arriving time ,an array of processing time and the quantum number q. Calculate the average waiting time of the system using Round Robin scheduling.

2. Rotate Matrix. Given a n by n matrix and a flag, return the matrix rotated right if flag == 1 else return the matrix rotated left.

3. Return the minimum sum of a path in a BST from node to leaf..本文原创自1point3acres论坛
. more info on 1point3acres
4. Insert value into a circular sorted linkedlist. (Given node may not be the smallest)

5. Greatest Common Divisor, given an array of integers, return the gcd of them. . 一亩-三分-地,独家发布

6. Shortest job first scheduling:
Given an array of arriving time and an array of processing time. Calculate the average waiting time of the system using shortest job first scheduling.
来源一亩.三分地论坛.
7. Count Cache Miss (LRU)
Given an array of integers and the size of a cache, return the cache miss count. (If cache hit, move this int to the tail, if size exceeds size, remove head)

8. Day change: given an array and number of days. Rules: if arr[i-1] == arr[i+1], arr = 0 else arr = 1, do that for n days.
Similar: leetcode Game of life https://leetcode.com/problems/game-of-life/
来源一亩.三分地论坛.
9. Find path in maze
Given a m*n matrix representing a Maze, 0 is a path and 1 is a wall. a mouse is at [0,0] and a cheese (represented as 9) is at [i, j]. Return true if there is a path from the mouse to the cheese else return false. .1point3acres网

(OA1) 10. Check subtree. Check weather t2 is a subtree of t1
. 留学申请论坛-一亩三分地
(OA1) 11. Valid parenthesis

(OA1) 12. reverse second half of linked list

13. Same Tree, check if 2 tree are the same

14. find out number of arithmetic sequence in array, if result > 1 billion return -1.

15. Amplitude, find the difference between the maximum and minimum value in a binary tree.

(OA1) 16. K closest point
. 围观我们@1point 3 acres
(OA1) 17. Find loop in Linked list / find the head of the loop

18. Given four integers, public int solution(int A, int B, int C, int D){}
变换他们的位置,使得,F(S) = abs(S[0]-S[1]) + abs(S[1]-S[2]) + abs(S[2]-S[3]) 最大。其中,S[0],S[1],S[2],S[3]就是ABCD要对应的位置。

(OA1) 19. window sum
. 牛人云集,一亩三分地


补充内容 (2016-3-4 01:06):
3/3 收到onsite。。。

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hurtlocker 发表于 2016-3-3 15:38:40 | 显示全部楼层
coding总结得很详细也全面,谢谢啦!

请问work simulation能再具体讲讲么?有复习资料可分享下?

貌似只能给你一个大米... 喏都给你了
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