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paiweilai 发表于 2017-7-2 01:15:39 | 显示全部楼层 |阅读模式

2017(4-6月) 码农类 博士 全职@Dropbox - 猎头 - Onsite |Pass在职跳槽

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A local candidate can choose to onsite 2 rounds instead of 2 phone screens.

Onsite 1:
- Find max horizon of an image. A horizon is a path from left to right (right, upper diagonal, lower diagonal) with value of min cell on the path. (DP)
- Allocate and release IDs. (queue, bitarray, segment tree)

Onsite 2:
- Behavior questions
- Find duplicate files
- Web crawler (multi-threading and locking mechanisms) (system design)
- Design Dropbox file sync feature (system design)
. visit 1point3acres.com for more.


. Waral 鍗氬鏈夋洿澶氭枃绔,

补充内容 (2017-7-2 04:56):
A number of a path can go to next column by left to right, left to upper diagonal, or left to lower diagonal (choose the min value as path). However, we want to find the max of all possible paths.

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edyyy 发表于 2017-7-2 03:59:43 | 显示全部楼层
“with value of min cell on the path” 什么意思啊?

补充内容 (2017-7-2 04:00):. Waral 鍗氬鏈夋洿澶氭枃绔,
Allocate and release IDs. (queue, bitarray, segment tree) 楼主能解释一下这题吗?谢谢
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 楼主| paiweilai 发表于 2017-7-2 04:57:26 | 显示全部楼层
edyyy 发表于 2017-7-2 03:59
“with value of min cell on the path” 什么意思啊?

补充内容 (2017-7-2 04:00):

allocate and release IDs is kinda similar to LC379.
you can also find many discussions in earlier posts.
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