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企盼黎明~ 发表于 2014-2-3 03:59 ![]()
This my work, so busy this week.
Does anyone know how to solve Movie-rating core set Q6 and social- ...
过了好久了==我都有点遗忘了,我直接把我写的贴上来了,你看下哪里不懂再跟我说?
欢迎其他同学看看,SQL可以写的很简单,也可以写的很复杂……我算写的复杂的了=。=
Movie-rating core set Q6
select name, title
from Movie, Reviewer, Rating R1, Rating R2
where Movie.mID=R1.mID and R1.rID=Reviewer.rID and R2.rID=Reviewer.rID and R2.mID = Movie.mID
and R1.stars<R2.stars
and R1.ratingDate<R2.ratingDate
social-network Mod Q3
insert into Friend
select distinct F1.ID1, F2.ID2
from Friend F1, Friend F2
where F1.ID2=F2.ID1 and F1.ID1 <> F2.ID2
and F1.ID1 not in (select F3.ID1 from Friend F3 where F3.ID2=F2.ID2); |
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