回复: 0
跳转到指定楼层
上一主题 下一主题
收起左侧

Karat interview for Crunchyroll

🔗
匿名用户-LQPFS  1 小时前 |倒序浏览

2026(10-12月) 码农类General 硕士 全职@karat - 内推 - 技术电面  | 😃 Positive 😐 Average | Other | 在职跳槽

注册一亩三分地论坛,查看更多干货!

您需要 登录 才可以下载或查看附件。没有帐号?注册账号

x
Part 1
You are a developer for a university. Your current project is to develop a system for students to find courses they share with friends. The university has a system for querying courses students are enrolled in, returned as a list of (ID, course) pairs.

Write a function that takes in a collection of (student ID number, course name) pairs and returns, for every pair of students, a collection of all courses they share.

Examples:

Sample Input:
enrollments1 = [
["58", "Linear Algebra"],
["94", "Art History"],
["94", "Operating Systems"],
["17", "Software Design"],
["58", "Mechanics"],
["58", "Economics"],
["17", "Linear Algebra"],
["17", "Political Science"],
["94", "Economics"],
["25", "Economics"],
["58", "Software Design"],
]
Sample Output (pseudocode, in any order):
find_pairs(enrollments1) =>
{
"58,17": ["Software Design", "Linear Algebra"]
"58,94": ["Economics"]
"58,25": ["Economics"]
"94,25": ["Economics"]
"17,94": []
"17,25": []
}
Additional test cases:
Sample Input:
enrollments2 = [
["0", "Advanced Mechanics"],
["0", "Art History"],
["1", "Course 1"],
["1", "Course 2"],
["2", "Computer Architecture"],
["3", "Course 1"],
["3", "Course 2"],
["4", "Algorithms"]
]
Sample output:
find_pairs(enrollments2) =>
{
"1,0":[]
"2,0":[]
"2,1":[]
"3,0":[]
"3,1":["Course 1", "Course 2"]
"3,2":[]
"4,0":[]
"4,1":[]
"4,2":[]
"4,3":[]
}
Sample Input:
enrollments3 = [
["23", "Software Design"],
["3", "Advanced M
您好!
本帖隐藏的内容需要积分高于 188 才可浏览
您当前积分为 0。
使用VIP即刻解锁阅读权限或查看其他获取积分的方式
游客,您好!
本帖隐藏的内容需要积分高于 188 才可浏览
您当前积分为 0。
VIP即刻解锁阅读权限 或 查看其他获取积分的方式
Unlock interview details and practice with AI
Popular Interview Questions from Top Companies
|   \    |            |  /
________    /                     \-->| Logic      |-+      _________
|          |   /   
__________        |________|  \     |           |
| Creative |  /     |            |                         \--->| Compilers |
| Writing  |-+----->| Databases  |                              |
_______|
|
______|  \     |________|-\     _____________________
           \                    \    |                       |
            \--------------------+-->| System Administration |
                                     |
_____________________|

Sample input 2:
all_courses_2 = [
["Course_3", "Course_7"],
["Course_0", "Course_1"],
["Course_1", "Course_2"],
["Course_2", "Course_3"],
["Course_3", "Course_4"],
["Course_4", "Course_5"],
["Course_5", "Course_6"],
]

Sample output 2 (in any order):
["Course_2", "Course_3"]

Complexity analysis variables:

n: number of pairs in the input
c: number of courses in the input

上一篇:Karat Interview for Crunchyroll
您需要登录后才可以回帖 登录 | 注册账号
隐私提醒:
  • ☑ 禁止发布广告,拉群,贴个人联系方式:找人请去🔗同学同事飞友,拉群请去🔗拉群结伴,广告请去🔗跳蚤市场,和 🔗租房广告|找室友
  • ☑ 论坛内容在发帖 30 分钟内可以编辑,过后则不能删帖。为防止被骚扰甚至人肉,不要公开留微信等联系方式,如有需求请以论坛私信方式发送。
  • ☑ 干货版块可免费使用 🔗超级匿名:面经(美国面经、中国面经、数科面经、PM面经),抖包袱(美国、中国)和录取汇报、定位选校版
  • ☑ 查阅全站 🔗各种匿名方法

本版积分规则

>
快速回复 返回顶部 返回列表