求问一道python题

已知一周七天的log
log = {car:[0,1,0,0,0,1,0],bus:[1,0,0,0,0,0,1],walk:[0,0,1,0,0,0,0]}
group = {overall:[car, bus, walk], vehicle:[car, bus]}
得结果 => {overall:[1,1,1,0,0,1,1], vehicle: [1,1,0,0,0,0,1]}

先谢谢各位大神，请问如何用最少的for loop做这道题。比方说什么zip(), any().

1. log = {
   
2.     "car": [0, 1, 0, 0, 0, 1, 0],
   
3.     "bus": [1, 0, 0, 0, 0, 0, 1],
   
4.     "walk": [0, 0, 1, 0, 0, 0, 0]
   
5. }
   
6. group = {
   
7.     "overall": ["car", "bus", "walk"],
   
8.     "vehicle": ["car", "bus"]
   
9. }
   
10. 
    
11. from functools import reduce
    
12. from operator import __or__
    
13. 
    
14. 
    
15. result = {
    
16.     group_name: reduce(lambda values, label: map(__or__, values, log[label]),
    
17.                        labels, [0] * 7)
    
18.     for group_name, labels in group.items()
    
19. }
    

复制代码

补充内容 (2021-2-4 04:10):
用__or__是把log里的0/1理解成表示存在性的bool类型了，如果求和的话把__or__替换成__add__就可以

不管怎么写都是O(n)的复杂度 本质上都是三个数组遍历一遍 用map甚至可以不出现for loop

vehicle = list(map(sum, zip(car, bus)))
overall = list(map(sum, zip(vehicle, walk)))