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sql练习题第二弹

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2023(1-3月) 分析|数据科学类 本科 其他@google - 网上海投 - 其他  | 😐 Neutral 🙂 Easy | Pass | 其他

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本帖最后由 黑发如漆的排球 于 2023-1-29 20:03 编辑

SQL练习题第二弹!-baidu 1point3acres
Q1. Write an SQL query to fetch “FIRST_NAME” from Worker table using the alias name as <WORKER_NAME>.
Ans.
The required query is:
Select FIRST_NAME AS WORKER_NAME from Worker;. Waral dи,
Q2. Write an SQL query to fetch “FIRST_NAME” from Worker table in upper case.
Ans.
The required query is:
Select upper(FIRST_NAME) from Worker;. 1point 3acres
Q3. Write an SQL query to fetch unique values of DEPARTMENT from Worker table..
Ans.
The required query is:
Select distinct DEPARTMENT from Worker;. From 1point 3acres bbs
Q4. Write an SQL query to print the first three characters of FIRST_NAME from Worker table.
Ans.-baidu 1point3acres
The required query is:. .и
Select substring(FIRST_NAME,1,3) from Worker;
Q5. Write an SQL query to find the position of the alphabet (‘a’) in the first name column ‘Amitabh’ from Worker table.. 1point 3acres
Ans.
The required query is:
Select INSTR(FIRST_NAME, BINARY'a') from Worker where. Waral dи,
FIRST_NAME = 'Amitabh';
Notes. ..
• The INSTR method is in case-sensitive by defaul
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Curated Interview Questions from Top Companies
with salaries >= 50000 and <= 100000.
Ans.. From 1point 3acres bbs
The required query is:
SELECT CONCAT(FIRST_NAME, ' ', LAST_NAME) As
Worker_Name, Salary
FROM worker
WHERE WORKER_ID IN
(SELECT WORKER_ID FROM worker
WHERE Salary BETWEEN 50000 AND 100000);.--
Q23. Write an SQL query to fetch the no. of workers for each department in the descending order.
Ans.
The required query is:.
SELECT DEPARTMENT, count(WORKER_ID) No_Of_Workers
FROM worker
GROUP BY DEPARTMENT. 1point3acres
ORDER BY No_Of_Workers DESC;
Q24. Write an SQL query to print details of the Workers who are also Managers.. check 1point3acres for more.
Ans.. 1point3acres
The required query is:
SELECT DISTINCT W.FIRST_NAME, T.WORKER_TITLE
FROM Worker W
INNER JOIN Title T. 1point3acres.com
ON W.WORKER_ID = T.WORKER_REF_ID
AND T.WORKER_TITLE in ('Manager');

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